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Laplace transform of the function f(t) is given by $${\text{F}}\left( {\text{s}} \right) = {\text{L}}\left\{ {{\text{f}}\left( {\text{t}} \right)} \right\} = \int_0^\infty {{\text{f}}\left( {\text{t}} \right){{\text{e}}^{ - {\text{st}}}}{\text{dt}}{\text{.}}} $$       Laplace transform of the function shown below is given by
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For a signal x(t) the Fourier transform is X(f). Then the inverse Fourier transform of X(3f + 2) is given by
Let x(t) ↔ X(jω) be Fourier Transform pair. The Fourier Transform of the signal x(5t - 3) in terms of X(jω) is given as
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Find the inverse Fourier transform of ej2t.