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For any given signal, average power in its 8 harmonic components as 50 mW each and fundamental component also has 50 mV power. Then, average power in the periodic signal is _______________

For any given signal, average power in its 8 harmonic components as 50 mW each and fundamental component also has 50 mV power. Then, average power in the periodic signal is _______________ Correct Answer 400

We know that according to Parseval’s relation, average power is equal to the sum of the average powers in all of its harmonic components. ∴ Pavg = 50×8 = 400.

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