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For any given signal, average power in its 6 harmonic components as 10 mW each and fundamental component also has 10 mV power. Then, average power in the periodic signal is _______________

For any given signal, average power in its 6 harmonic components as 10 mW each and fundamental component also has 10 mV power. Then, average power in the periodic signal is _______________ Correct Answer 60

We know that according to Parseval’s relation, average power is equal to the sum of the average powers in all of its harmonic components. ∴ Pavg = 10 × 6 = 60.

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