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The value of the c1 in the following equation is? i = e-37.5t(c1cos1290t + c2sin1290t) + 0.7cos(500t + π/4 + 88.5⁰).

The value of the c1 in the following equation is? i = e-37.5t(c1cos1290t + c2sin1290t) + 0.7cos(500t + π/4 + 88.5⁰). Correct Answer 0.5

At t = 0 that is initially the current flowing through the circuit is zero that is i = 0. So, c1 = -0.71cos (133.5⁰) = 0.49.

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