Moment of inertia of a triangle having base as b and height as h and axis is along the centroid and parallel the base.

Moment of inertia of a triangle having base as b and height as h and axis is along the centroid and parallel the base. Correct Answer b*h3/36

The moment of inertia is sum of products of areas and squares of perpendicular distances from center of gravity. And this gives the moment of inertia of any planar section.

Related Questions

According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. $$I$$P) is given by (where, A = Area of the section, $$I$$G = Moment of inertia of the section about an axis passing through its C.G. and h = Distance between C.G. and the parallel axis.)
According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. $${I_{\text{P}}}$$) is given by (where, A = Area of the section, $${I_{\text{G}}}$$ = Moment of inertia of the section about an axis passing through its C.G. and h = Distance between C.G. and the parallel axis.)