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A point in 2nd quadrant is 12 units away from the horizontal plane and vertical plane 13 units away from both the profile plane. Orthographic projections are drawn find the distance from the side view and top view.

A point in 2nd quadrant is 12 units away from the horizontal plane and vertical plane 13 units away from both the profile plane. Orthographic projections are drawn find the distance from the side view and top view. Correct Answer 25

Given the point is in 2nd quadrant. Since here distance from side view and top view is asked for that we need the distance between the front view and side view (12+13); front view and top view (12-12) and these lines which form perpendicular to each other gives needed distance, answer is √(252+02 ) = 25units.

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