If, Fhp(u, v)=F(u, v) – Flp(u, v) and Flp(u, v) = Hlp(u, v)F(u, v), where F(u, v) is the image in frequency domain with Fhp(u, v) its highpass filtered version, Flp(u, v) its lowpass filtered component and Hlp(u, v) the transfer function of a lowpass filter. Then, unsharp masking can be implemented directly in frequency domain by using a filter. Which of the following is the required filter?

If unsharp masking can be implemented directly in frequency domain by using a composite filter: Hhp(u, v) = 1 – Hlp(u, v), where Hlp(u, v) the transfer function of a lowpass filter. Then, the composite filter for High-boost filtering is __________

A

Hhb(u, v) = 1 – Hhp(u, v)

B

Hhb(u, v) = 1 + Hhp(u, v)

C

Hhb(u, v) = (A-1) – Hhp(u, v), A is a constant

D

Hhb(u, v) = (A-1) + Hhp(u, v), A is a constant

Unsharp masking can be implemented directly in frequency domain by using a filter: Hhp(u, v) = 1 – Hlp(u, v), where Hlp(u, v) the transfer function of a lowpass filter. What kind of filter is Hhp(u, v)?

A

Composite filter

B

M-derived filter

C

Constant k filter

D

None of the mentioned

In frequency domain terminology, which of the following is defined as “obtaining a highpass filtered image by subtracting from the given image a lowpass filtered version of itself”?

A

Emphasis filtering

B

Unsharp masking

C

Butterworth filtering

D

None of the mentioned

Which of the following gives an expression for high boost filtered image fhb, if f represents an image, f blurred version of f, fs unsharp mask filtered image and A ≥ 1?

A

fhb = (A – 1) f(x, y) + f(x, y) – f x, y)

B

fhb = A f(x, y) – f(x,y)

C

fhb = (A – 1) f(x, y) + fs(x, y)

D

All of the mentioned

If we use a Laplacian to obtain sharp image for unsharp mask filtered image fs(x, y) of f(x, y) as input image, and if the center coefficient of the Laplacian mask is negative then, which of the following expression gives the high boost filtered image fhb, if ∇2 f represent Laplacian?

A

fhb = A f(x, y) – ∇2 f(x,y)

B

fhb = A f(x, y) + ∇2 f(x,y)

C

fhb = ∇2 f(x,y)

D

None of the mentioned

The transfer function of High frequency emphasis is given as: Hhfe(u, v) = a + b Hhp(u, v), for Hhp(u, v) being the highpass filtered version of image,a≥0 and b>a. for certain values of a and b it reduces to High-boost filtering. Which of the following is the required value?

A

a = (A-1) and b = 0,A is some constant

B

a = 0 and b = (A-1),A is some constant

C

a = 1 and b = 1

D

a = (A-1) and b =1,A is some constant

Which of the following statements are correct? 1. A lowpass filter passes low frequencies and stops high frequencies. 2. A highpass filter passes high frequencies and rejects low frequencies 3. A bandpass filter passes frequencies within a frequency band and attenuates frequencies outside the band. 4. A bandstop filter passes frequencies within the band and blocks/attenuates frequencies outside a frequency band.

A

1, 2 and 4 only

B

1, 3 and 4 only

C

2, 3 and 4 only

D

1, 2 and 3 only

A process that accentuate the contribution to enhancement made by high-frequency components, by multiplying the highpass filter by a constant and adding an offset to the highpass filter to prevent eliminating zero frequency term by filter is known as _______

A

Unsharp masking

B

High-boost filtering

C

High frequency emphasis

D

None of the mentioned

Which of the following are true? (i) A programming language option does not permit global variables of any king and has no nesting of procedures/functions, but permits recursion can be implemented with static storage allocation (ii) Multi-level access link (or display) arrangement is needed to arrange activation records-only if the programming language being implemented has nesting of procedures/function (iii) Recursion in programming languages cannot be implemented with dynamic storage allocation (iv) Nesting of procedures/functions and recursion require a dynamic heap allocation scheme and cannot be implemented with a stack-based allocation scheme for activation records (v) Languages which permit a function to return a function as its result cannot be implemented with a stack-based storage allocation scheme for activation records.

A

(ii) and (v) only

B

(i), (iii) and (iv) only

C

(i), (ii) and (v)

D

(ii), (iii) and (v) only

There are two domains on your network. The DESIGN domain trusts the SALES domain. A color printer is shared in the DESIGN domain, and print permissions have been granted to the Domain Users and Domain Guests groups in the DESIGN domain. The Guest account has been enabled in the DESIGN domain. User John Y logs on using his account in the SALES domain. What must you do to allow JohnY to access the printer?

A

Make JohnY a member of the DESIGN Domain Guests group

B

Make JohnY a member of the DESIGN Domain Users group

C

Do nothing. JohnY can access the printer now

D

JohnY cannot access the printer with this configuration

E

None of the above

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