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A company recruits candidates satisfying the following criteria -  1. Candidates who secured at least 85% in standard 10th or equivalent. 2. Candidates who secured at least 65% in standard 12th or equivalent. 3. Candidates who are not from commerce background. Who among the following candidates will the company definitely select? A. Jitesh is a science student having scored 70% in standard 12th and 80% in 10th with an excellent sports background. B. Jignesh scored 80% in standard 12th, 90% in standard 10th and secured 2nd place in his college among all commerce students. C. Jayesh scored 75% in standard 10th, 75% in standard 12th and is an arts student. D. Jinesh secured 80% in standard 12th, 88% in standard 10th and is a science student with great acting skills
The given table shows the number of students and their class. Division A students are scholars who get a 25% rebate in fees. In addition, all girls students get 40% subsidy. If the fee per student a year WITHOUT rebate or subsidy is Rs. 10,000, then find the total fees collected from the students of these 6 classes for that year. Division  /Standard  Boys Girls Division A /Standard 9 20 40 Division B /Standard 9 40 35 Division C /Standard 10 20 20 Division A /Standard 10 40 20 Division B /Standard 10 20 40 Division C /Standard 10 20 15
Refer the below data table and answer the following Question : Division/Standard Boys Girls Division A/Standard 5 20 30 Division B/Standard 5 15 20 Division C/Standard 5 30 10 Division A/Standard 6 30 25 Division B/Standard 6 30 25 Division C/Standard 6 30 20   What is the ratio of Boy’s to Girl’s? 
For a standard normal variate, the value of Standard Deviation is ___________
The standard deviation of a standard normal variate will be
What percentage of scores falls within three standard deviations from the mean for the normal variate?
The standard normal cumulative probability function (probability from $$ - \infty $$  to xn) can be approximated as $${\text{F}}\left( {{{\text{x}}_{\text{n}}}} \right) = \frac{1}{{1 + {\text{exp}}\left( { - 1.7255{{\text{x}}_{\text{n}}}{{\left| {{{\text{x}}_{\text{n}}}} \right|}^{0.12}}} \right)}}$$       where xn = standard normal deviate. If mean and standard deviation of annual precipitation are 102 cm and 27 cm respectively, the probability that the annual precipitation will be between 90 cm and 102cm is
A class of first year B. Tech. students is composed of four batches A, B, C and D, each consisting of 30 students. It is found that the sessional marks of students in Engineering Drawing in batch Chave a mean of 6.6 and standard deviation of 2.3. The mean and standard deviation of the marks for the entire class are 5.5 and 4.2, respectively. It isdecided by the course instructor to normalize the marks of the students of all batches to have the same mean and standard deviation as that of the entire class. Due to this, the marks of a student in batch C are changed from 8.5 to
If X1 ∼ N (2, 1) and X2 ∼ N (3, 1), then X1 + X2 will be a normal variate whose mean will be
Let X be a random variable following normal distribution with mean +1 and variance 4. Let Y be another normal variable with mean -1 and variance unknown. If P(X ≤ -1) = P(Y ≥ 2) the standard deviation of Y is