Bissoy.com
Doctors Medicines MCQs Q&A

Consider its input resistance to be R1. Now, the bypass capacitor is attached, so that the new input resistance is R2. Given that hie = 1000Ω and hfe = 50, find R1-R2.

Consider its input resistance to be R1. Now, the bypass capacitor is attached, so that the new input resistance is R2. Given that hie = 1000Ω and hfe = 50, find R1-R2. Correct Answer 112.2Ω

For the circuit, CE amplifier without bypass capacitor, input resistance, R1=hie + (1+hfe)RE R1 = 1000 + 51*2.2 = 1000 + 112.2 = 1112.2Ω With a bypass capacitor attached, input resistance, R2 = hie = 1000Ω Thus R1 – R2 = 112.2Ω.

Related Questions

In the given circuit, hfe = 50 and hie = 1000Ω, find overall input and output resistance.
Given hfe = 60, hie=1000Ω, hoe = 20μ Ω–, hre = 2 * 10-4. Find the current gain of the BJT, correct up to two decimal points.
Consider the following circuit, where source current = 10mA, hfe = 50, hie = 1100Ω, then for the transistor circuit, find output resistance RO and input resistance RI.
For the given circuit, input resistance RI = 20Ω, hfe = 50. Output resistance = ∞. Find the new values of input and output resistance, if a base resistance of 2kΩ is added to the circuit.
A transistor has hie =2kΩ, hoe=25µmhos and hfe=60 with an unbypassed emitter resistor Re=1kΩ. What will be the input resistance and output resistance?
A transistor has hie =1KΩ and hfe=60 with an bypassed emitter resistor Re=1kΩ. What will be the input resistance and output resistance?
Which of these is false for a CS amplifier without a bypass capacitor compared to a CS amplifier with a bypass capacitor?
Consider the circuit. Given hfe = 50, hie = 1200Ω. Find voltage gain.
A transistor has hfe=100, hie=2kΩ, hoe=0.005mmhos, hre=0. Find the output impedance if the lad resistance is 5kΩ.
In a clapp oscillator with three capacitor C1, C2, C3, C1 is used as upper capacitor in voltage divider, C2 is used as lower capacitor in voltage divider and C3 is the third capacitor. For perfect operation which of these capacitor should have minimum value?