Let a and b be complex cube roots of unity. If x=7a+2b and y=2a+7b, then evaluate xy.
Let a and b be complex cube roots of unity. If x=7a+2b and y=2a+7b, then evaluate xy. Correct Answer 53
Write a=ω and b=ω2. Now, xy=(7a+2b)(2a+7b)=(7ω+2ω2)(2ω+7ω2)=14ω2+14ω+53=39 (since, 1+ω+ω2=0).
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Feb 20, 2025
