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Find the area of a function f(x) = x2 + xCos(x) from x = 0 to a, where, a>0.

Find the area of a function f(x) = x2 + xCos(x) from x = 0 to a, where, a>0. Correct Answer a3⁄3 + aSin(a) + Cos(a) – 1

Given, f(x) = x2 + xCos(x) Hence, F(x) = ∫x2 + xCos(x) dx = x3⁄3 + xSin(x) + Cos(x) Hence, area inside f(x) is, F(a) – F(0) = a3⁄3 + aSin(a) + Cos(a) – 1.

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