The multiplicative inverse of 0x95 in AES where m(x)=x8+x4+x3+x+1 is
The multiplicative inverse of 0x95 in AES where m(x)=x8+x4+x3+x+1 is Correct Answer 0x8A
The multiplicative inverse is 0x8A.
মোঃ আরিফুল ইসলাম
Feb 20, 2025