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Solve for x: log2(x2-3x)=log2(5x-15).

Solve for x: log2(x2-3x)=log2(5x-15). Correct Answer 3, 5

By using the property if logax = logay then x=y, gives 2x2-3x=10-6x. Now, to solve the equation x2-3x-5x+15=0 ⇒ x2-8x+15 ⇒ x=3, x=5 For x=3: log2(32-3*3) = log2(5*3-15) ⇒ true For x=5: log2(52-3*5) = log2(5*5-15) ⇒ true The solutions to the equation are : x=3 and x=5.

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