Which of the following is the base case for 4n+1 > (n+1)2 where n = 2?
Which of the following is the base case for 4n+1 > (n+1)2 where n = 2? Correct Answer 64 > 9
Statement By principle of mathematical induction, for n=2 the base case of the inequation 4n+1 > (n+1)2 should be 64 > 9 and it is true.
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Feb 20, 2025