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What is the result of compiling and running the following code? class Base{ public Base(){ System.out.print("Base"); } } public class Derived extends Base{ public Derived(){ this("Examveda"); System.out.print("Derived"); } public Derived(String s){ System.out.print(s); } public static void main(String[] args){ new Derived(); } }

What is the result of compiling and running the following code? class Base{ public Base(){ System.out.print("Base"); } } public class Derived extends Base{ public Derived(){ this("Examveda"); System.out.print("Derived"); } public Derived(String s){ System.out.print(s); } public static void main(String[] args){ new Derived(); } } Correct Answer BaseExamvedaDerived

Answer: Option 3

1. new Derived(); statement executes and invoke the non-parametrized constructor of derived class i.e. public Derived(); 2. As Derived class is a subclass of class Base so super(); executes and calls the super class constructor and prints "Base". 3. After that this("Examveda"); executes and call the parametrized constructor public Derived(String s); of Derived class as this always refer to the current object. So, it prints "Examveda". 4. Lastly the print statement executes and prints "Derived" Hence output is BaseExamvedaDerived.

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