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How many two input AND gates and two input OR gates are required to realize Y = BD + CE + AB?

How many two input AND gates and two input OR gates are required to realize Y = BD + CE + AB? Correct Answer 3, 2

There are three product terms. So, three AND gates of two inputs are required. As only two input OR gates are available, so two OR gates are required to get the logical sum of three product terms.

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