How many two-input AND and OR gates are required to realize Y = CD+EF+G?
How many two-input AND and OR gates are required to realize Y = CD+EF+G? Correct Answer 2, 2
Y = CD + EF + G The number of two input AND gate = 2 The number of two input OR gate = 2.
মোঃ আরিফুল ইসলাম
Feb 20, 2025