When applying miller’s theorem to resistors, resistance R1 is for node 1 and R2 for node 2. If R1>R2, then for same circuit, then for capacitance for which the theorem is applied, which will be larger, C1 or C2?
When applying miller’s theorem to resistors, resistance R1 is for node 1 and R2 for node 2. If R1>R2, then for same circuit, then for capacitance for which the theorem is applied, which will be larger, C1 or C2? Correct Answer C1
Given R1>R2 R/1-K > R/1-K-1, and so 1-K-1>1-K Thus K2>1, K>1, K<-1 (correct) Thus, C1=C(1-K) and C2=C(1-K-1) Hence C1>C2.
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Feb 20, 2025