For an ideal non-inverting operational amplifier having finite gain (A), the ratio of output voltage (v0) to input voltage (vi) is (given R2 is the feedback resistance)

While performing an experiment to determine the gain for an ideal operational amplifier having finite gain, a student mistakenly used the equation 1 + R2/R1 where R2 is the feedback resistance. What is the percentage error in his result? Given A is the finite voltage gain of the ideal amplifier used.

A

(R2/R1)/(A+ R2/R1) X 100%

B

(1+R2/R1)/(A+R2/R1) X 100%

C

(1+R2/R1)/(A+1+R2/R1) X 100%

D

(R2/R1)/(A+1+R2/R1) X 100%

An amplifier without feedback has a voltage gain of 50, input resistance of 1 kΩ & Output resistance of 2.5 kΩ.The input resistance of the current shunt negative feedback amplifier using the above amplifier with a feedback factor of 0.2 is

A

$$\frac{1}{{11}}{\text{k}}\Omega $$

B

$$\frac{1}{5}{\text{k}}\Omega $$

C

5 kΩ

D

11 kΩ

The finite voltage gain of a non-inverting operational amplifier is A and the resistance used is R1 and R2 in which R2 is the feedback resistance. Under what conditions it can one use the expression 1 + R2/R1 to determine the gain of the amplifier?

A

A ~ R2/R1

B

A >> R2/R1

C

A << R2/R1

D

None of the mentioned

An amplifier of gain 1000 is made into a feedback amplifier by feeding 9.9% of its output voltage in series with the input opposing. If f_L = 20 Hz and f_H = 200 kHz for the amplifier without feedback, then due to the feedback

A

the gain decreases by 10 times

B

the output resistance increases by 10 times

C

the f_H increases by 100 times

D

the input resistance decreases by 100 times

Consider a voltage series feedback network, where amplifier gain = 100, feedback factor = 5. For the basic amplifier, input voltage = 4V, input current=2mA. Find the input resistance of the network.

A

1.002kΩ

B

1002kΩ

C

2kΩ

D

2000kΩ

An amplifier is measured to have an internal resistance of 10 kΩ, voltage gain of 100V/V and output resistance of 100 Ω. Also, when a load resistance of 1 kΩ is connected between the output resistance if found to decrease to 8 kΩ. If the amplifier is fed with the signal source having an internal resistance of 2 kΩ. Find Gm.

A

1 A/V

B

10 A/V

C

100 A/V

D

1000 A/V

An amplifier is measured to have an internal resistance of 10 kΩ, voltage gain of 100V/V and output resistance of 100 Ω. Also, when a load resistance of 1 kΩ is connected between the output resistance if found to decrease to 8 kΩ. If the amplifier is fed with the signal source having an internal resistance of 2 kΩ. Find Av.

A

9.09 V/V

B

10 V/V

C

90.9 V/V

D

100 V/V

An amplifier is measured to have an internal resistance of 10 kΩ, voltage gain of 100V/V and output resistance of 100 Ω. Also, when a load resistance of 1 kΩ is connected between the output resistance if found to decrease to 8 kΩ. If the amplifier is fed with the signal source having an internal resistance of 2 kΩ. Find Gvo.

A

53.3 V/V

B

63.3 V/V

C

73.3 V/V

D

83.3 V/V

An amplifier is measured to have an internal resistance of 10 kΩ, voltage gain of 100V/V and output resistance of 100 Ω. Also, when a load resistance of 1 kΩ is connected between the output resistance if found to decrease to 8 kΩ. If the amplifier is fed with the signal source having an internal resistance of 2 kΩ. Find Gv.

A

53.4 V/V

B

72.7 V/V

C

83.3 V/V

D

90.9 V/V

An amplifier is measured to have an internal resistance of 10 kΩ, voltage gain of 100V/V and output resistance of 100 Ω. Also, when a load resistance of 1 kΩ is connected between the output resistance if found to decrease to 8 kΩ. If the amplifier is fed with the signal source having an internal resistance of 2 kΩ. Find R out.

A

146 Ω

B

292 Ω

C

584 Ω

D

1168 Ω

For an ideal non-inverting operational amplifier having finite gain (A), the ratio of output voltage (v0) to input voltage (vi) is (given R2 is the feedback resistance)

Related Questions