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Consider an abrupt PN junction. Let V0 be the built in potential of this junction and VR be the reverse bias voltage applied. If the junction capacitance Cj is 1pF for V0+VR =1V, then for V0+VR =4V what will be the value of Cj?

Consider an abrupt PN junction. Let V0 be the built in potential of this junction and VR be the reverse bias voltage applied. If the junction capacitance Cj is 1pF for V0+VR =1V, then for V0+VR =4V what will be the value of Cj? Correct Answer 0.5Pf

We know, Cj1/ Cj2=1/2 Cj2=Cj1(1/4)1/2=1/2 . We get Cj2=1/2=0.5pF.

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