A speech signal has a total duration of 20 sec. It is sampled at the rate of 8 kHz and then PCM encoded. The signal-to-quantization noise ratio is required to be 40 dB. The minimum storage capacity needed to accommodate this signal is

A speech signal has a total duration of 20 sec. It is sampled at the rate of 8 kHz and then PCM encoded. The signal-to-quantization noise ratio is required to be 40 dB. The minimum storage capacity needed to accommodate this signal is Correct Answer 140 KBytes

(SNR)q = 1.76 + 6.02(n) = 40 dB, n = 6.35 We take the n = 7. Capacity = 20 x 8k x 7 = 1.12 Mbits = 140 Kbytes.
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