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If the velocity of a charged particle in perpendicular electric and magnetic field is 7.27 X 106m/s and the Electric field is 6 X 106 N/c, what should be the value of magnetic field for velocity sector?

If the velocity of a charged particle in perpendicular electric and magnetic field is 7.27 X 106m/s and the Electric field is 6 X 106 N/c, what should be the value of magnetic field for velocity sector? Correct Answer 0.83 T

As we know, for velocity selector, v = E/B Therefore, B = E/v = 6 X 106/7.27 X 106 = 0.83 T.

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