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Calculate the energy released by the fission of 5 gm of 235U in kWh if energy released per fission is 200 MeV.

Calculate the energy released by the fission of 5 gm of 235U in kWh if energy released per fission is 200 MeV. Correct Answer 1.13 X 105 kWh

Now, Number of atoms in 5 g of 235U = 6.023 X 1023 X 5/235 Energy released by the fission = 6.023 X 1023 X 5 X 200 X 1.6 X 10-19 / 235 = 4.1 X 1011J 1.13 X 105 kWh.

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