The reaction NO2 + CO → NO + CO2 takes place in two steps. Find the rate law. 2NO2 → NO + NO3 (k1) – slow NO3 + CO → CO2 + NO2 (k2) – fast 3 b) R = k2 c) R = k1 d) R = k1 2

The reaction NO2 + CO → NO + CO2 takes place in two steps. Find the rate law. 2NO2 → NO + NO3 (k1) – slow NO3 + CO → CO2 + NO2 (k2) – fast 3 b) R = k2 c) R = k1 d) R = k1 2 Correct Answer NO2

In any reaction the slowest step is the rate determining step, the rate of the overall reaction depends on this step. So, 2NO2 → NO + NO3(k1) is the rate determining step. Therefore the rate law R= k12.

Related Questions

For reaction system given below, volume is suddenly reduced to half of its value by increasing the pressure on it. If the reaction is of first order with respect to O2 and second order with respect to NO, what will be the change in the rate of reaction? 2NO(g) + O2(g) + 2NO2(g)