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If 103n + 24k + 1. 9 + k, is divisible by 11, then what is the least positive value of k?

If 103n + 24k + 1. 9 + k, is divisible by 11, then what is the least positive value of k? Correct Answer 10

P(n) = 103n + 24k + 1. 9 + k P(1) = 103 + 25 . 9 + k P(1) = 1000 + 288 + k P(1) = 1288 + k When 1288 is divided by 11, the remainder is 1. Therefore, 1287 is divisible by 11. The next number that is divisible is 1298. k = 1298 – 1288 k = 10

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