logax=1, log, y=2 ,logaz=3,loga(x3y2z)=?

logax=1, log, y=2 ,logaz=3,loga(x3y2z)=? Correct Answer 4

loga(x3y2z) = loga(x3y2) - logaz  [.; logaMN = logaM - logaN] = logax3  +  logay2 - logaZ  = 3×1  + 2×2  - 3  = 4

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