logax=1, log, y=2 ,logaz=3,loga(x3y2z)=?
A
1
B
4
C
2
D
5
Correct Answer: 4
loga(x3y2z) = loga(x3y2) - logaz [.; logaMN = logaM - logaN] = logax3 + logay2 - logaZ = 3×1 + 2×2 - 3 = 4