logax=1, log, y=2 ,logaz=3,loga(x3y2z)=?
logax=1, log, y=2 ,logaz=3,loga(x3y2z)=? Correct Answer 4
loga(x3y2z) = loga(x3y2) - logaz [.; logaMN = logaM - logaN] = logax3 + logay2 - logaZ = 3×1 + 2×2 - 3 = 4
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Feb 20, 2025