Nucleus of 233U92 emits which particles to give nucleus of 225Ra88?

Nucleus of 233U92 emits which particles to give nucleus of 225Ra88? Correct Answer 2α

CONCEPT:

• Nuclear Decay: Nuclear decay is the process by which an unstable isotope of a particular element spontaneously transforms into a new element by the emission of ionizing radiation. Example: Decay of C-14 to C-12.
• In the fission reaction α, β, and γ rays are released.

• α-decay: when an α particle is leaving the parent atom
  • It reduces the atomic number (Z) by 2.
  • It reduces the atomic mass (A) by 4.
• β-decay: when a β particle is leaving the parent atom
  • It increases the atomic number (Z) by 1.
  • It does not change in atomic mass.
• γ - Decay: it neither changes the atomic number nor atomic mass.

​Calculation:

Given that,

Parent nuclei = 233U92 

Daughter nuclei =  ²²⁵Ra₈₈ + 233 - 225X92 - 88 

In the given condition the decay can b expressed as 

²³³U₉₂ →²²⁵Ra₈₈ + 8X4 

 Thus from the above equation, we can conclude that after decay atomic mass is decreased by 8 and the atomic number was decreased by 4 

Hence we can conclude that 2 alpha particle or helium particle will be given out in this radioactive decay 

i.e., 233U92 →225Ra88 + 2 ⁴He₂