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What will be the atomic number and mass of product element B respectively if an atomic number and atomic mass of element A is 92 and 238 respectively? A → B + 22He4

What will be the atomic number and mass of product element B respectively if an atomic number and atomic mass of element A is 92 and 238 respectively? A → B + 22He4 Correct Answer 88, 230

The correct answer is 88, 230

Concept:

  • Alpha Radioactive decay:
  • α-decay is a type of radioactive decay.
  • In this, an atomic nucleus emits an alpha particle i.e helium nucleus and another element with energy.
  • It decreases the atomic number by 2 and atomic mass by 4.

​​Explanation:

  • The given reaction is the reaction of Alpha Radioactive Decay.
    • The Alpha particle is a helium nucleus 42He.
    •  eg. 23892U → 23490Th + 42He
    • If element A has atomic no - 92
    • Then element B has atomic no = 92 - 2 * 2 = 88
    • Mass of element B = 238 - 2 * 4 = 230

Notes:

  • Beta Radioactive Decay:
    •  Nucleus decays spontaneously by emitting an electron or a positron.
    • eg. 3215P → 3216S + e– + v–
    • In this decay atomic number of product, elements increase by one.

 

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