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Vishwanathan Anand has won 80% of the chess games he has played so far in the tournament. Anand's goal is to win 90% of all the games he has to play in the tournament. If he had already played 15 games out of the total 50 games that he has to play, then what is the maximum number of games he can afford to lose in the remaining games and still be able to achieve his goal?

Vishwanathan Anand has won 80% of the chess games he has played so far in the tournament. Anand's goal is to win 90% of all the games he has to play in the tournament. If he had already played 15 games out of the total 50 games that he has to play, then what is the maximum number of games he can afford to lose in the remaining games and still be able to achieve his goal? Correct Answer 2

Calculation:

Total no. of games in the tournament = 50

No. of games already played = 15

Percentage of games won in already played games = 80%

⇒ No. of games won out of 15 games played = 15 × (80/100) = 12

Also given, his goal is to win 90% of all the games,

⇒ Total no. of games won out of total no. of games = 50 × (90/100) = 45

Now, Remaining no. games to be played = 50 - 15 = 35

As we have calculated, he has won 12 out of 15 games that are already played,

⇒ No. of games that he should win out of 35 games = 45 - 12 = 33

So, maximum no. of games he can afford to lose in the remaining games = 35 - 33 = 2

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