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Team A and B play in a Basket Ball tournament. A match can have three outcomes; (i) A win (ii) B win (iii) Tie. The team has to win two games to be declared as winner. The first team winning two games in a row is declared as a winner and tournament ends. In how many ways the tournament can proceed where one team can be declared as winner? 

Team A and B play in a Basket Ball tournament. A match can have three outcomes; (i) A win (ii) B win (iii) Tie. The team has to win two games to be declared as winner. The first team winning two games in a row is declared as a winner and tournament ends. In how many ways the tournament can proceed where one team can be declared as winner?  Correct Answer 10

Given:

For winning the match a team has to win 2 matches

Calculation:

Let M1 be 1st match, M2 be 2nd match, M3 be 3rd match

And let W represents winning match, L represents losing match and 

T represents tie match 

Now, The first condition is for team A 

Matches M1 M2  M3
Results for A W W  
Results for A W L W
Results for A W T W
Results for A L W W
Results for A W T W

Here, There are five ways for team A 

Similarly, the same results can be for B.

Hence, The total number of possible ways is 10.

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