Smaller diagonal of a rhombus is equal to length of its sides. If length of each side is 4 cm, then what is the area (in square cm) of an equilateral triangle with side equal to the bigger diagonal of the rhombus?
Smaller diagonal of a rhombus is equal to length of its sides. If length of each side is 4 cm, then what is the area (in square cm) of an equilateral triangle with side equal to the bigger diagonal of the rhombus? Correct Answer 12√3
Given:
Length of each side = 4 cm = length of smallest diagonal
Concept used:
Diagonals of the rhombus bisect each other.
Also, diagonals are perpendicular to each other.
Calculation:
Let the longest diagonal be d.
42 = 22 + (d/2)2
16 - 4 = d2/4
12 × 4 = d × d
d = 4√3
Side of the equilatral triangle = 4√3
Area of the triangle = (√3/4) × a2 = (√3/4) × (4√3) × (4√3)
Area of the triangle = 12√3 cm2.
∴ The area of the triangle is 12√3 cm2.
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Feb 20, 2025