Smaller diagonal of a rhombus is equal to length of its sides. If length of each side is 4 cm, then what is the area (in square cm) of an equilateral triangle with side equal to the bigger diagonal of the rhombus?

Smaller diagonal of a rhombus is equal to length of its sides. If length of each side is 4 cm, then what is the area (in square cm) of an equilateral triangle with side equal to the bigger diagonal of the rhombus? Correct Answer 12√3

Given:

Length of each side = 4 cm = length of smallest diagonal

Concept used:

Diagonals of the rhombus bisect each other.

Also, diagonals are perpendicular to each other.

Calculation:

Let the longest diagonal be d.

42 = 22 + (d/2)2

16 - 4 = d2/4

12 × 4 = d × d 

d = 4√3

Side of the equilatral triangle = 4√3

Area of the triangle = (√3/4) × a2 = (√3/4) × (4√3) × (4√3)

Area of the triangle = 12√3 cm2.

∴ The area of the triangle is 12√3 cm2.

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