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A person walks along edge of a square park of side 20 m covering two sides then start walking on diagonal till he covers 1/4th distance of whole diagonal and then starts walking on path of smaller square field. Then he covers two sides and again starts walking on diagonal of bigger Square Park. Then find distance covered by him? (Take value of √2 = 1.4)

A person walks along edge of a square park of side 20 m covering two sides then start walking on diagonal till he covers 1/4th distance of whole diagonal and then starts walking on path of smaller square field. Then he covers two sides and again starts walking on diagonal of bigger Square Park. Then find distance covered by him? (Take value of √2 = 1.4) Correct Answer 74

According to question, let

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From A to B,

Distance = 20 m

From B to C,

Distance = 1/4th × diagonal of square

i.e. Distance = 1/4th × 20√2 = 5√2

Now for calculating CD, we know diagonal of square containing CD is half the diagonal of big square,

So CD√2 = 1/2 × 20√2 = 10√2

CD = 10 = DE

∴ Total distance = AB + BC + CD + DE + EF + FA = 20 + 5√2 + 10 + 10 + 5√2 + 20 = 74 m

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