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A bullet of mass 0.05 kg is fired with a velocity of 120 ms-1 from a rifle of mass 4 kg. What will be the recoil velocity of the rifle?

A bullet of mass 0.05 kg is fired with a velocity of 120 ms-1 from a rifle of mass 4 kg. What will be the recoil velocity of the rifle? Correct Answer 1.5 ms<sup>-1</sup>

Concept:

Law of Conservation of Linear Momentum: If no external force acts on a system (called isolated) of constant mass, the total momentum of the system remains constant with time.

According to the law of conservation of momentum:

m1u1 + m2u2 = m1v1 + m2v2 

Where m1,m2 = Masses of two bodies, u1, u2 = Initial velocities of the bodies, v1, v2 = Final velocities of the bodies

Calculation:

Given:

m1 = 0.05 kg, m2 = 4 kg, u1 = 120 ms-1, u2 = ? 

Total momentum should be conserved,

∴ m1u1 = m2u2 

0.05 × 120 = 4 × u2 

u2 = 1.5 ms-1

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