25 liters are drawn from a vessel full of wine and is then filled with water. This operation is performed one more time. The ratio of the quantity of wine now left in the vessel to that of the water is 36 : 85. How much wine the vessel hold initially?

25 liters are drawn from a vessel full of wine and is then filled with water. This operation is performed one more time. The ratio of the quantity of wine now left in the vessel to that of the water is 36 : 85. How much wine the vessel hold initially? Correct Answer 55 liters

Given:

25 liters are drawn from a vessel full of wine and is then filled with water. This operation is performed one more time.

The ratio of the quantity of wine now left in the vessel to that of the water is 36 : 85. 

Concept used:

Wine left = Initial amount of wine × n, where n is the number of times the wine is replaced

Calculation:

Let the initial quantity of wine be y litres

Amount of wine left = y × (1 - 25/y)2 

Ratio of wine left to initial quantity of wine = y × (1 - 25/y)2/y = (1 - 25/y)2  

⇒ 36/(36 + 85) = (1 – 25/y)2 

⇒ 36/121 = (6/11)2 = (1 – 25/y)2 

⇒ 6/11 = 1 – 25/y

On Solving, y = 55 liters

∴ 55 litres

Related Questions

Each question below is followed by two statements I and II. You have to determine whether the data given in the statements are sufficient for answering the question. You should use the data and your knowledge of Mathematics to choose the best possible answer. What is the ratio of coconut oil and milk in the final beaker? If contents from four vessels poured in it. I. Vessel B has 10 ml more capacity than vessel A and the ratio of coconut oil and milk in vessel B is 2 ∶ 7. Vessel C has coconut oil and milk in the ratio 2 ∶ 3 and contains 38 ml more capacity than Vessel D II. Vessel A has milk and coconut oil in the ratio 3 ∶ 5. Vessel C has 12 ml more coconut oil than vessel D.