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A horizontal beam is shown below The distance of the point of contra flexure from the end ‘A’ is

A horizontal beam is shown below The distance of the point of contra flexure from the end ‘A’ is Correct Answer 0.666 m

Explanation:

Given,

Reaction at Support B, RB = 16 kN

Let 'x' be the distance from Support 'C'

BM at a distance x from the free end

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BMx = 0

(10 × x) – (16 × (x - 0.5)) = 0

10 × (x) = 16 × (x) - 8

6x = 8

∴ x = 1.33 m

∴ From end A, distance = 2 - 1.333 = 0.667 m

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