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Anil and Balbeer can finish a task in 3 days. They started working together, but after 2 days Anil got injured. Balbeer took 2 more days to finish the task. In how many days can Balbeer alone finish the same task?

Anil and Balbeer can finish a task in 3 days. They started working together, but after 2 days Anil got injured. Balbeer took 2 more days to finish the task. In how many days can Balbeer alone finish the same task? Correct Answer 6

Given:

Anil and Balbeer can finish a task = 3 days

They worked together = 2 days

Balbeer took more days to finish the task = 2

Calculation:

LCM of 2 and 3 is 6

Anil and Balbeer do work = 6/3

⇒ 2 units/day

Anil and Balbeer 2 days work = 2 × 2 = 4 units

Work left = 6 – 4 = 2 units

Remaining work is done by Anil in 2 days

Anil's per day work = 2/2 = 1 unit/day

Balbeer's per unit work = (Anil + Balbeer)'s work – Anil's work

⇒ 2 – 1 = 1 unit/day

Balbeer alone can finish the same task = 6/1

⇒ 6 days

∴ Balbeer alone can finish the same task is 6 days

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