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Consider a three-phase. 50 Hz, 11 kV distribution system, Each of the conductors is suspended by an insulator string having two identical porcelain insulators. The self-capacitance of the insulator is 5 times the shunt capacitance between the link and the ground, as shown in the figure. The voltage across the two insulators are

Consider a three-phase. 50 Hz, 11 kV distribution system, Each of the conductors is suspended by an insulator string having two identical porcelain insulators. The self-capacitance of the insulator is 5 times the shunt capacitance between the link and the ground, as shown in the figure. The voltage across the two insulators are Correct Answer <span style="">e1 = 3.46 kV, e2 = 2.89 kV</span>

Given that

Line voltage = 11 kV

Frequency = 50 Hz

k = shunt capacitance between link and ground / self-capacitance of insulator = 1/5 = .2

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And we know that,

Vph = e1 + e2

(11/√3) kV = e1 + e2      ---------------  (1)

e1 = (1 + k) e2      

e1 = 1.2 e2               -------------- (2)

From (1) and (2)

e1 = 3.46 kV, e2 = 2.89 kV

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