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A long solenoid has 500 turns. When a current of 2 amperes is passed through it, the resulting magnetic flux linked with each turn of the solenoid is 4 × 10–3 Wb. The self-inductance of the solenoid is -

A long solenoid has 500 turns. When a current of 2 amperes is passed through it, the resulting magnetic flux linked with each turn of the solenoid is 4 × 10–3 Wb. The self-inductance of the solenoid is - Correct Answer 1.0 henry

Concept:

Solenoid: The solenoid is a long cylindrical coil of wire consisting of a large number of turns bound together very tightly.

Magnetic flux: The Number of magnetic lines of forces set up in a magnetic circuit is called magnetic flux. It is analogous to an electric current, I is an electric circuit. Its SI unit is Weber

The Self-Inductance of the solenoid is given by:

 L = N (ϕB/ i)

L = self-inductance. N = number of turns. ,ϕB = Magnetic flux linked with each turn of the solenoid, i =  current flowing  through the solenoid

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Explanations:​

Given that:

N = 500 , ϕB  =  4 × 10-3 , i = 2 Ampere

L = (500 × 4 × 10-3) / 2 

L =  1.0 henry.

hence option 1 is correct.

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