When a capacitor was connected across the terminals of an ohm meter, the pointer indicated a low resistance initially and then slowly came back to very high resistance. This indicates that capacitor is

When a capacitor was connected across the terminals of an ohm meter, the pointer indicated a low resistance initially and then slowly came back to very high resistance. This indicates that capacitor is Correct Answer All right

Concept: 

Capacitor behavior:

• Ohmmeter uses dc voltage (battery) to measure the unknown resistance.
• Then the capacitor is subjected to dc source, initially, it acts as a short circuit and at steady-state, it acts as an open circuit.
• At the time when the ohmmeter is connected to the capacitor, the capacitor acts as a short circuit, so low resistance is indicated.
• After some time, the capacitor behaves as an open-circuit, so the pointer moves to the final position.
• This states that the capacitor is in very good condition to be used.

Important Points

• Capacitive reactance is given by Xc = 1/(2πfc) where f = frequency and c = value of capacitance
• Frequency f = 1/T (Time period) 
• At the instant when the capacitor is connected to dc source, then V volt is reached in 0 sec so the time period is 0 sec.
• This makes the frequency to be infinity, therefore capacitive reactance becomes zero.
• That's why the capacitor acts as a short circuit initially when the dc source is applied. 
• Now capacitor starts charging and voltage is developed across it.
• When the steady-state voltage across the capacitor is equal to source voltage, then after that it doesn't allow any current to pass through it.
• Therefore, acts as highly resistive or this can also be seen when at steady-state, frequency is zero, so capacitive reactance becomes infinity.
• That's why the capacitor blocks dc at the steady-state condition.