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A shopkeeper cheats both his wholesaler and customer. While buying he uses a machine that shows 1000 g instead of 1350 g and while selling uses a machine which shows 1000 g for 750 g. However the customer demands a discount of 8%, so he hikes the marked price by 10% and allows a discount of 8%. Find the approximate profit percentage of the shopkeeper.

A shopkeeper cheats both his wholesaler and customer. While buying he uses a machine that shows 1000 g instead of 1350 g and while selling uses a machine which shows 1000 g for 750 g. However the customer demands a discount of 8%, so he hikes the marked price by 10% and allows a discount of 8%. Find the approximate profit percentage of the shopkeeper. Correct Answer  82%

GIVEN :

While buying he uses a machine that shows 1000 g instead of 1350 g and while selling uses a machine which shows 1000 g for 750 g. 

 

ASSUMPTION :

Let price of 1 g be Re. 1

 

CALCULATION :

While buying he gets 1350 g for 1000 g

While selling he gives 750 g for 1000 g

On this transaction he gains 600 g for every 750 g sold

Thus we have,

SP of 750 g = Rs. 1350

If the SP is increased by 10%

= 1.1 × 1350 = Rs. 1485

And then allows a discount of 8%

SP of 750 g = 0.92 × 1485 = Rs. 1366.2

∴ Profit earned = 1366.2 - 750 =  616.2

Profit % = (616.2/750) × 100 = 82% (approx.)

 

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