In ΔABC and ΔDEF, if AB = DE, AC = EF and BC = DF, then which of the following is correct?

In ΔABC and ΔDEF, if AB = DE, AC = EF and BC = DF, then which of the following is correct? Correct Answer <span style="">Δ</span>ABC <span style="">≅</span> <span style="">Δ</span>EDF

Given:

AB = DE, AC = EF and BC = DF

Concept used:

Side-Side-Side (SSS) congruence theorem: The two triangles are said to be congruent if three of their sides are equal to the corresponding sides of the other triangle.

Calculation:

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Here, AB = DE, AC = EF and BC = DF

The corresponding side of ΔABC and ΔEDF are equal.

ΔABC and ΔEDF are congruent by Side-Side-Side (SSS) congruence theorem.

Therefore, ΔABC ≅ ΔEDF

Related Questions

In ΔABC and ΔDEF, AB = DE and BC = EF, then one can infer that ΔABC ≅ ΔDEF, when
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