For a triangle ABC, D, E, F are the mid - point of its sides. If ΔABC = 24 sq. units then ΔDEF is :

For a triangle ABC, D, E, F are the mid - point of its sides. If ΔABC = 24 sq. units then ΔDEF is : Correct Answer 6 sq. units

According to question,
Triangles mcq solution image
As we know that
Given: area of ΔABC = 24 square units
As we know that
D, E and F are the midpoint of AB, AC and BC
∴ Area of ΔADE = area of ΔDBF
= area of ΔDEF = area of ΔEFC
∴ Area of ΔDEF = $$\frac{1}{4}$$ area of ΔABC
Area of ΔDEF = $$\frac{1}{4}$$ × 24
Area of ΔDEF = 6 sq. units

Related Questions

The question is followed by two statements I and II. What is the area of ΔDEF? (I) D, E, F are mid-points of the sides of ΔABC (II) Area of ΔABC is 10 sq. units.
How far is point 'R' from Point 'T'? Statement (I): Point 'R' is 5 metres to the north of point 'M'. Point 'U' is 4 metres to the east of point 'R'. Point 'T' is to the west of point 'R' such that points 'U' 'R' and 'T' form a straight line of  metres. Statement (II): Point 'Z' is metres to the south of point 'T'. Point 'U' is  metres to the east of point 'T'. Point 'M' is  metres to the east of point 'Z'. Point 'R' is  metres to the north of point 'M'. Point 'R' lies on the line formed by joining points 'T' and 'U'.
In ΔABC and ΔDEF, AB = DE and BC = EF, then one can infer that ΔABC ≅ ΔDEF, when