A person has 45 coins of 50p, 1 rupee, and 2 rupee coins in ratio 6: 2: 1. Which of the following combinations will yield the same amount of total money if a person has 25p, 50p, and 1 rupee coins. (the order of is 25p, 50p, and 1 rupee and the total number of coins).
A person has 45 coins of 50p, 1 rupee, and 2 rupee coins in ratio 6: 2: 1. Which of the following combinations will yield the same amount of total money if a person has 25p, 50p, and 1 rupee coins. (the order of is 25p, 50p, and 1 rupee and the total number of coins). Correct Answer 6 : 5 : 3, 70
25 paisa = 0.25 Rs., 50 paisa = 0.5 Rs.
Actual money with the person = 0.5((6/9) × 45) + 1((2/9) × 45) + 2((1/9) × 45) = 15 + 10 + 10 = Rs. 35
Now we have to check from the given option that, If coins are in order of 25p, 50p, and 1 rupee, then which ratio and amount will yield the same amount as Rs. 35.
Total money in the First case:
Total value of coins = 0.25((6/9) × 45) + 0.50((2/9) × 45) + 1((1/9) × 45) = 7.5 + 5 + 5 = Rs. 17.50
Total money in the Second case:
Total value of coins = 0.25((3/5) × 80) + 0.50((1/5) × 80) + 1((1/5) × 80) = Rs. 36
Total money in the Third case:
Total value of coins = 0.25((6/14) × 70) + 0.50((5/14) × 70) + 1((3/14) × 70) = Rs. 35
In the third case, the amount is the same
