Bissoy.com
Doctors Medicines MCQs Q&A

Which of the following statement(s) is/are TRUE? I. \(\sqrt {324} + \sqrt {3.24} + \sqrt {0.0324} = 19.98\) II. \(\sqrt {129 + \sqrt {121} + \sqrt {361} + \sqrt {100} } = 13\)

Which of the following statement(s) is/are TRUE? I. \(\sqrt {324} + \sqrt {3.24} + \sqrt {0.0324} = 19.98\) II. \(\sqrt {129 + \sqrt {121} + \sqrt {361} + \sqrt {100} } = 13\) Correct Answer Both I and II

Considering statement I,

⇒ √324 = 18

⇒ √3.24 = √(324/100) = 18/10 = 1.8

⇒ √0.0324 = √(324/10000) = 18/100 = 0.18

⇒ √324 + √3.24 + √0.0324 = 18 + 1.8 + 0.18 = 19.98

Considering statement II,

⇒ √(129 + √121 + √361 + √100)

= √(129 + 11 + 19 + 10)

= √169 = 13

∴ Both the statement are true

Related Questions

Which one of the following four addresses is NOT EXACTLY the same as the one given below? Robert S Ingram 1998 Revocable 8 Shaftsbury Ln Hilton Head Island, SC 29926 (843) 342­7094 (i) Robert S Ingram 1998 Revocable 8 Shaftsbury Ln Hilton Head Island, SC 29926 (843) 342­7094 (ii) Robert S Ingram 1998 Revocable 8 Shaftsbury Ln Hilton Head Island, SC 29926 (843) 342­7094 (iii) Robert S Ingram 1998 Revocable 8 Shaftsbary Ln Hilton Head Island, SC 29926 (843) 342­7094 (iv) Robert S Ingram 1998 Revocable 8 Shaftsbury Ln Hilton Head Island, SC 29926 (843) 342­7094
Which of the following statement(s) is/are TRUE? (I) \(\sqrt {144} \times \sqrt {36} < \sqrt[3]{{125}} \times \sqrt {121}\) (II) \(\sqrt {324} + \sqrt {49} > \sqrt[3]{{216}} \times \sqrt 9\)
Which of the following is TRUE? \({\rm{I}}.{\rm{\;}}\sqrt[3]{{11}} > \sqrt 7 > \sqrt[4]{{45}}\) \({\rm{II}}.{\rm{\;}}\sqrt 7 > \sqrt[3]{{11}} > \sqrt[4]{{45}}\) \({\rm{III}}.{\rm{\;}}\sqrt 7 > \sqrt[4]{{45}} > \sqrt[3]{{11}}\) \({\rm{IV}}.{\rm{\;}}\sqrt[4]{{45}} > \sqrt 7 > \sqrt[3]{{11}}\)
Which of the following is TRUE? \({\rm{I}}.{\rm{\;}}\frac{1}{{\sqrt[3]{{12}}}} > \frac{1}{{\sqrt[4]{{29}}}} > \frac{1}{{\sqrt 5 }}\) \({\rm{II}}.\;\frac{1}{{\sqrt[4]{{29}}}} > \frac{1}{{\sqrt[3]{{12}}}} > \frac{1}{{\sqrt 5 }}\) \({\rm{III}}.\;\frac{1}{{\sqrt 5 }} > \frac{1}{{\sqrt[3]{{12}}}} > \frac{1}{{\sqrt[4]{{29}}}}\) \({\rm{IV}}.{\rm{\;}}\frac{1}{{\sqrt 5 }} > \frac{1}{{\sqrt[4]{{29}}}} > \frac{1}{{\sqrt[3]{{12}}}}\)
Simplify : $$\frac{1}{{\sqrt 3 + \sqrt 4 }} \,+ $$   $$\frac{1}{{\sqrt 4 + \sqrt 5 }} \,+ $$   $$\frac{1}{{\sqrt 5 + \sqrt 6 }} \,+ $$   $$\frac{1}{{\sqrt 6 + \sqrt 7 }} \,+ $$   $$\frac{1}{{\sqrt 7 + \sqrt 8 }}\, + $$   $$\frac{1}{{\sqrt 8 + \sqrt 9 }} = ?$$
Subscription received in 1998:
For the year 1997
For the year 1998
For the year 1999
Subscription outstanding on 31st December, 1998 was Rs. 4,000. What amount of subscription will appear in income and Expenditure account of 1998:
Which of the following statement(s) is/are TRUE? I. \(\sqrt{1}+ \sqrt{2} + \sqrt{3} + \sqrt{4}+ \sqrt{5} + \sqrt{6} > 10\) II. \(\sqrt{(10)} + \sqrt{(12)} + \sqrt{(14)} > 3 \sqrt{(12)}\)
Determined the value of $$\frac{1}{{\sqrt 1 + \sqrt 2 }}{\text{ + }}$$  $$\frac{1}{{\sqrt 2 + \sqrt 3 }}\, + $$   $$\frac{1}{{\sqrt 3 + \sqrt 4 }}\, + $$   $$...... + $$   $$\frac{1}{{\sqrt {120} + \sqrt {121} }}{\text{ = ?}}$$
If the value of \(\frac{{3x\sqrt y + 2y\sqrt x }}{{3x\sqrt y - 2y\sqrt x }} - \frac{{3x\sqrt y - 2y\sqrt x }}{{3x\sqrt y + 2y\sqrt x }}\) is same as that of \(\sqrt x\sqrt y\), then which of the following relations between x and y is correct?
$$\frac{1}{{\left( {\sqrt 9 - \sqrt 8 } \right)}} \, - $$   $$\frac{1}{{\left( {\sqrt 8 - \sqrt 7 } \right)}} \, + $$   $$\frac{1}{{\left( {\sqrt 7 - \sqrt 6 } \right)}} \, - $$   $$\frac{1}{{\left( {\sqrt 6 - \sqrt 5 } \right)}} \, + $$   $$\frac{1}{{\left( {\sqrt 5 - \sqrt 4 } \right)}}$$   is equal to ?