If 3rd, 8th and 13th terms of a GP are p, q and r respectively, then which one of the following is correct?

If 3rd, 8th and 13th terms of a GP are p, q and r respectively, then which one of the following is correct? Correct Answer q<sup>2</sup> = pr

Concept:

If a is the first term and r is the common ratio of a GP then the nth term of GP is given by: an = arn - 1

Calculation:

Given: 3rd, 8th and 13th terms of a GP are p, q and r respectively.

Let a is the first term and R is the common ratio.

⇒ a3 = aR2 = p     ---(1)

⇒ a8 = aR7 = q    ----(2)

⇒ a13 = aR12 = r     ---(3)

Dividing (2) by (1), we get

⇒ q / p = R5          ---(4)

Similarly, by dividing (3) by (2), we get

⇒ r / q = R5          ---(5)

From (4) and (5), we get

⇒ q2 = p × r

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