If a disc has moment of inertia I about the axis which is tangential and in plane of the disc, then the moment of inertia about the axis which is tangential and perpendicular to its plane will be:

If a disc has moment of inertia I about the axis which is tangential and in plane of the disc, then the moment of inertia about the axis which is tangential and perpendicular to its plane will be: Correct Answer <span class="math-tex">\(\dfrac{6}{5}I\)</span>

CONCEPT:

Theorems on Moment of Inertia:

Parallel axis theorem

The moment of inertia of a body about an axis parallel to the body passing through its center is equal to the sum of moment of inertia of the body about the axis passing through the center and product of the mass of the body times the square of the distance between the two axes.

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Related Questions

According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. $$I$$P) is given by (where, A = Area of the section, $$I$$G = Moment of inertia of the section about an axis passing through its C.G. and h = Distance between C.G. and the parallel axis.)
According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through center of gravity (i.e. $${I_{\text{P}}}$$) is given by (where, A = Area of the section, $${I_{\text{G}}}$$ = Moment of inertia of the section about an axis passing through its C.G. and h = Distance between C.G. and the parallel axis.)
The moment of inertia of a thin disc of mass ‘m’ and radius ‘r’, about an axis through its center of gravity and perpendicular to the plane of the disc is