The moment of inertia of a thin disc of mass ‘m’ and radius ‘r’, about an axis through its center of gravity and perpendicular to the plane of the disc is
A
$$\frac{{{\text{m}}{{\text{r}}^2}}}{2}$$
B
$$\frac{{{\text{m}}{{\text{r}}^2}}}{4}$$
C
$$\frac{{{\text{m}}{{\text{r}}^2}}}{6}$$
D
$$\frac{{{\text{m}}{{\text{r}}^2}}}{8}$$
Correct Answer: $$\frac{{{\text{m}}{{\text{r}}^2}}}{2}$$