The moment of inertia of a thin rod of mass 'm' and length '$$l$$', about an axis through its centre of gravity and perpendicular to its length is
A
$$\frac{{{\text{m}}{l^2}}}{4}$$
B
$$\frac{{{\text{m}}{l^2}}}{6}$$
C
$$\frac{{{\text{m}}{l^2}}}{8}$$
D
$$\frac{{{\text{m}}{l^2}}}{{12}}$$
Correct Answer: $$\frac{{{\text{m}}{l^2}}}{{12}}$$