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108 apples were distributed among 5 kids A, B, C, D and E. The ratio of numbers of apples with B, C and D is 5 ∶ 6 ∶ 8. The ratio of number of apples with A and C is 2 ∶ 3. The number of apples with E is 16. Which 2 kids got the same number of apples?

108 apples were distributed among 5 kids A, B, C, D and E. The ratio of numbers of apples with B, C and D is 5 ∶ 6 ∶ 8. The ratio of number of apples with A and C is 2 ∶ 3. The number of apples with E is 16. Which 2 kids got the same number of apples? Correct Answer A, E

Given:

108 apples were distributed among 5 kids A, B, C, D and E.

The ratio of numbers of apples with B, C and D is 5 ∶ 6 ∶ 8.

The ratio of number of apples with A and C is 2 ∶ 3.

The number of apples with E is 16.

Formula:

If the ratio of A and B is a ∶ b, assume A = ak and B = bk

Where k is a constant.

Calculation:

There were 108 apples

B

D

C

A

5

8

6

 

 

 

3 × 2 = 6

2 × 2 = 4

5

8

6

4


Now, A ∶ B ∶ C ∶ D = 4 ∶ 5 ∶ 6 ∶ 8

According to question

⇒ 4x + 5x + 6x + 8x + 16 = 108

⇒ 23x = 92

⇒ x = 4

So, A got 4x = 16 apples

A = E = 16 apples

∴ A and E got the same number of apples

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