Bissoy.com
Doctors Medicines MCQs Q&A

In which of the following scenarios is the centre of pressure of a submerged body equal to the distance of center of gravity of the body from free space?

In which of the following scenarios is the centre of pressure of a submerged body equal to the distance of center of gravity of the body from free space? Correct Answer Horizontal plane surface

Explanation:

The total pressure is the force exerted by a static fluid on a surface either plane or curved when the fluid comes in the contact of the surface. This force always acts normal to the surface.

Centre of pressure:

It is the point of application of total pressure on the surface. There are four cases of the submerged surface.

  • Vertical plane surface
  • Horizontal plane surface
  • Inclined plane surface
  • Curved surface

 

The total pressure force on the surface is given by,

F = ρgAh̅ 

where A = area of the surface in contact with liquid, h̅ = height of centroid of the body from the free liquid surface.

For a horizontal surface, as every point of the surface is at the same depth from the free surface of the liquid, the pressure intensity will be equal on the entire surface.

[ alt="F1 Krupalu Madhuri 04.01.2021 D5 " src="//storage.googleapis.com/tb-img/production/22/01/F1_Krupalu_Madhuri_04.01.2021_D5_.png" style="width: 271px; height: 179px;">

Related Questions

From the data given: 54tr xc Connecting rod of mass 2 kg and the distance between the centre of crank and centre of gudgeon pin is 25 cm. The Center of Gravity lies at a point 10 cm from the gudgeon pin along the line of centres. The radius of gyration of this system about an axis through the Center of Gravity perpendicular to the plane of rotation is 11 cm. Find the mass placed at distance l2 from center of gravity.
An Internal combustion engine has a connecting rod of mass 2 kg and the distance between the centre of crank and centre of gudgeon pin is 25 cm. The Center of Gravity lies at a point 10 cm from the gudgeon pin along the line of centres. The radius of gyration of this system about an axis through the Center of Gravity perpendicular to the plane of rotation is 11 cm. Find the mass located at gudgeon pin in Kg.
An Internal combustion engine has a connecting rod of mass 2 kg and the distance between the centre of crank and centre of gudgeon pin is 25 cm. The Center of Gravity lies at a point 10 cm from the gudgeon pin along the line of centres. The radius of gyration of this system about an axis through the Center of Gravity perpendicular to the plane of rotation is 11 cm. If two masses are used instead of the connecting rod, one at the gudgeon pin and other at the crank pin. What will be the new radius of gyration?
An Internal combustion engine has a connecting rod of mass 2 kg and the distance between the centre of crank and centre of gudgeon pin is 25 cm. The Center of Gravity lies at a point 10 cm from the gudgeon pin along the line of centres. The radius of gyration of this system about an axis through the Center of Gravity perpendicular to the plane of rotation is 11 cm. If two masses are used instead of the connecting rod, one at the gudgeon pin and other at the crank pin, if the angular acceleration of the rod is 23 000 rad/s2, then find the correction couple in N-m.
Given steps in procedure to find the center of gravity of the quadrilateral ABCD. Arrange the steps. i. Draw lines joining G1 with G2 and G3 with G4. ii. In given quadrilateral draw diagonal BD and locate centers of gravity G1, G2 of triangles BCD and ABD. iii. The point of intersection of lines G1G2 and G3G4 gives the center of gravity of the quadrilateral ABCD. iv. Similarly draw the diagonal AC and determine the centers of gravity G3, G4 of triangles ABC and ADC.
What would be the total pressure on a submerged block making an angle 0° with the fluid surface? (where A is area submerged and x is gauge pressure on an elemental area (yh*) and h* are the distance of the centroid of the area from the free surface of the liquid)
The periodic time of a compound pendulum is __________ when the distance between the point of suspension and the center of gravity is equal to the radius of gyration of the body about its center of gravity.
The periodic time of a compound pendulum is …….. when the distance between the point of suspension and the center of gravity is equal to the radius of gyration of the body about its center of gravity.
A vertical rectangular plane surface is submerged in water such that its top and bottom surfaces are 1.5 m and 6.0 m res-pectively below the free surface. The position of center of pressure below the free surface will be at a distance of
A body "A" of weight 10 kg with its center of gravity 25 cm from the axis of rotation is to be balanced by another body ‘B’ of weight 5 kg. The radius at which the center of gravity of weight ‘B’ should be placed is